Imagine taking that spherical surface, and pushing it into this new shape. This ought to mean that when you hit a ball it gets cold: Then we get to the impact.
This heating is due to the extreme distortion and thus again friction of the ball during impact: This leads me to believe that air resistance had an affect of the bounce height due to terminal velocity no longer being in control.
This means the graph should look like this: Towards the end of my experiment, the graph shows a clear place where a factor influenced my results.
The distortion requires you to change the contact area. I think that the two forces will balance each other out therefore the object will not be affected by the air resistance because of the weight. The lateral force that this generates dissipates heat - so energy is lost instead of being stored in the elasticity of the ball.
As the results and the graph attached overleaf shows, the line of best fit indicates that my prediction was correct, although due to experimental error it is not exact.
I would expect to get a result of approximately 22 when dropping from one metre; however I actually got about The surface is always an important factor in this investigation because if changed during the recording of results the bounce height and elastic potential energy could be affected greatly.
When Elastic Potential Energy occurs, sound waves, movement and little heat is made throughout the surface it hits and therefore this can also be a factor I could measure. Look at this picture: There are still rules you will have to follow though to try and keep the conditions roughly the same throughout the investigation.
The picture on the right is the "actual" state: This will cause the dissipation of some of the energy of the ball into energy of the air turbulence, heating, flow. However, as the end column displaying the percentage loses shows, although the percentage losses vary they are all around the same point.
Of course for an air filled ball, there are losses associated with the compression of the air: Moreover, I cannot be certain that when I drop the ball I will not exert some force.
By doing this I can change the heights and measure the different energy factors involved. You can think of it as the mass of the ball being mounted to a spring that compresses when you hit the floor - but there will be some friction both inside the ball, and particularly between the ball and the floor which will dissipate energy: The last three points are some what away form the trend of the rest; this could be because I had reached a point where terminal velocity concluded.
However, during the fall, it will experience drag from the air. All this combines to give a particular ball and surface combination something called the coefficient of restitution - a number that expresses how much of the energy of the ball before the impact is "given back" restitution noun: Therefore the percentage loss increases near the end as the drop height increases.
The surface used to drop the ball onto. Therefore I would use the same surface each time. The maximum kinetic energy it can gain is equal to the potential energy it can lose. The picture in the middle is the "fully compressed" state in which all energy of motion would have been converted to elastic energy.
You can find this out by one simple equation similar to the one before. How large this effect is will depend on the ball, the height, One variable for example, conditions of atmosphere, is very hard to keep under control as it is a natural atmosphere and if you wanted to make it perfect other equipment and scientific knowledge will need to be known.
As you do so, ball rubs against floor. These last results are anomalies as they do not follow the trend of the rest, and are notably away from the line of best fit.
When the ball hits the ground and then bounces back up again, the amount of potential energy the second time is not as great as from when you first started. Plan During this experiment there will be many factors that you will have to take into consideration as each one could have an effect on the investigation and we only want to change one of these factors to make it a fair test.
Some of the variables are simple and easy to keep under control but others could cause problems or are difficult to keep under control.
The Percentage Energy Loss is the second Potential Energy divided by the first Potential energy then multiplied by one hundred.
If outdoors then out of the rain otherwise it would affect the mass of the ball by making it heavier and therefore affecting the elastic potential energy.Sep 17, · I know that U/m (potential energy) is equal to E/m (mechanical energy) of the ball when it is in free flight but I'm not sure how to find the mechanical energy lost between mi-centre.com I just subtract the values and the difference is the loss?
If a ball hits the floor after an acceleration then why does it bounces lower? I mean the Energy is passed to the floor then why does the floor give back less Energy? Why does a ball bounce lower?
Ask Question. another loss is due to friction with air: although this is generally small for a ball heavy enough, this would still prevent. Apr 16, · Energy loss in bouncing ball? Does a ball lose the same percentage of energy after each bounce?
how would you calculate the kinetic energy of the ball upon impact given the heights of the bounces and the mass of the ball?Status: Resolved. The percentage energy loss - Sample Essay.
When the ball hits the ground and then bounces back up again, the amount of potential energy the second time is not as great as from when you first started. This is because of Percentage Energy Loss and Elastic Potential Energy. The Percentage Energy Loss is the second Potential Energy divided by.
Length =Thermal energy transferred (J) Length (cm). Current (Amps) Power (Watts) From these results we can work out the coulombs of charge in each separate length of nichrome. This result will then allow us to calculate how many electrons had passed through the wire, which further allows us to calculate the time taken for the experiment to take place.
The bounce of a ball Rod Cross Physics Department, University of Sydney, Australia The energy loss can be predicted approximately from measurements of the static hysteresis curve obtained by plot-ting the ball compression as a function of applied force for a.Download